Python Tutorial to study Python programming with examples

Full Python Tutorial for Novices Playlist : https://www.youtube.com/watch?v=hEgO047GxaQ&t=0s&index=2&checklist=PLsyeobzWxl7poL9JTVyndKe62ieoN-MZ3

Python Tutorial in Hindi : https://www.youtube.com/watch?v=JNbup20svwU&checklist=PLk_Jw3TebqxD7JYo0vnnFvVCEv5hON_ew

Github :- https://github.com/navinreddy20/Python-

On this video we are going to see:

– For loop

– Distinction between for loop and whereas loop

– The place to make use of for loop

– Syntax of for loop

– Instance of for loop

– Nested for loop

– For loop with assortment

– For loop with vary

Enhancing Displays :

https://amzn.to/2RfKWgL

https://amzn.to/2Q665JW

https://amzn.to/2OUP21a.

Try our web site: http://www.telusko.com

Comply with Telusko on Twitter: https://twitter.com/navinreddy20

Comply with on Fb:

Telusko : https://www.fb.com/teluskolearn…

Navin Reddy : https://www.fb.com/navintelusko

Comply with Navin Reddy on Instagram: https://www.instagram.com/navinreddy20

Subscribe to our different channel:

Navin Reddy : https://www.youtube.com/channel/UCxmk…

Telusko Hindi :

https://www.youtube.com/channel/UCitz…

Donation:

PayPal Id : navinreddy20

Patreon : navinreddy20

http://www.telusko.com/contactus

Extra Studying :

Python for Novices :- https://bit.ly/3x2g23h

Django Tutorial for Novices :- https://bit.ly/3GyNqS6

JavaScript Tutorial for Novices :- https://bit.ly/3NGR3ba

Node JS Tutorial for Novices:- https://bit.ly/3N82IQy

Java Tutorial For Novices :- https://bit.ly/3z8HWfq

Relaxation Api | Restful Internet Service :-https://bit.ly/3axANLo

Servlet and JSP Tutorial for Novices :- https://bit.ly/3M0FhqH

Spring Framework with Maven Tutorial :- https://bit.ly/3LWByL3

Design Patterns in Java :- https://bit.ly/3a9VjSa

Docker Fundamentals:- https://bit.ly/38DNLqo

Blockchain Tutorial for Novices :- https://bit.ly/3x33f0z

The Web3 Present:- https://bit.ly/3M4znF0

Corda Tutorial:- https://bit.ly/3Q2Zwrg

Hyperledger Material :- https://bit.ly/3PMFJfD

NoSQL Tutorial for Novices :- https://bit.ly/3m03Ycq

Sql Tutorial for Novices :- https://bit.ly/3GyWWEU

Mysql Tutorial :- https://bit.ly/3M4C6OK

Knowledge Buildings utilizing Java :- https://bit.ly/3t5HPNY

Knowledge Buildings utilizing C :- https://bit.ly/3GBLoAE

Kotlin Tutorial:- https://bit.ly/3x1kOfV

Git Tutorial for Novices:- https://bit.ly/3NMbmUw

C Programming Tutorial :- https://bit.ly/3x4bA45

supply

Homework today:

import math

print('Perfect square numbers 1-50')

for i in range(1,51):

if math.sqrt(i).is_integer() == True:

print(i)

I compiled it and it worked well, but I hope if you can tidy it up for me

Quiz ans:

i = 1

while True:

x = i * i

if x >= 500:

break

else:

print(x)

i += 1

Answer to the question

# The numbers will be printed in one line, separated by a space

for i in range(1,501):

if (i**2) <= 500:

print(i**2, ' ', end="")

else:

break

In range( ), when we are going in descending order, I realized the first number is included and the last number is excluded, just like when we go in ascending order. Nice to learn that as well.

import math

for i in range(1,51):

x=math.pow(i,2)

print(i)

Hello naveen your explarion is good me very easy to understand.so explain loops deapth

How would you create a for loop to find two large numbers if the user has to enter 10 numbersβ¦.Without using a list ?

Answer:

Method(1)

for i in range(1, 501):

for j in range(1, (i+1)):

if i == j**2:

print(i)

Method(2)

from math import *

for i in range(1, 501):

for j in range(1, (i+1)):

if sqrt(i)==int(j):

print(i)

from math import sqrt

for i in range(1, 500, 1):

a = int(sqrt(i))

if a == sqrt(i):

print(i)

Kuchh dikhai nahi deta

for i in range(1, 501):

if pow(i, 2) >= 500:

pass

else:

print(pow(i, 2))

for i in range(1,51):

i= i*i

print(i)

awesome

Answer:

import math

for i in range(1,501):

sq_rt = math.sqrt(i)

if (int(sq_rt)**2) == i:

print('Perfect Square', i)

In code 3.40 you have already told I take every Value but in Paul it print like Paul only why can't

P

A

U

L

from math import *

for n in range(1, 500):

if int(sqrt(n)) ** 2 == n:

print(n, end=' ')

Even we can use continue right

Hi Navin how we can apply three different condition by using for loop

which IDE are you using?

sir, where is tour assigment coipes

i would love if you did loop over more complicated data structures such as dataframe.. nice video

for x in range(1,500)

if x**2<=500

print(i**2)

Knows his stuff but talks way too fast… Using subtitles obstruct the output window.

You are a takla alien π½

nice explaination

it is easy by this teacher πππππππππππ

good job

Sir, please could you explain this total = 0

N= 5

for i in range (1, N=1):

for j in range (1, i+1):

total += 1

print(total)

for i in range(1,51):

if(i**2<=50):

print(i)

else:

print(end="")